2x^2-8y+2=0

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Solution for 2x^2-8y+2=0 equation: 


Simplifying
2x2 + -8y + 2 = 0

Reorder the terms:
2 + 2x2 + -8y = 0

Solving
2 + 2x2 + -8y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 2x2 + -2 + -8y = 0 + -2

Reorder the terms:
2 + -2 + 2x2 + -8y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2x2 + -8y = 0 + -2
2x2 + -8y = 0 + -2

Combine like terms: 0 + -2 = -2
2x2 + -8y = -2

Add '8y' to each side of the equation.
2x2 + -8y + 8y = -2 + 8y

Combine like terms: -8y + 8y = 0
2x2 + 0 = -2 + 8y
2x2 = -2 + 8y

Divide each side by '2'.
x2 = -1 + 4y

Simplifying
x2 = -1 + 4y

Reorder the terms:
1 + x2 + -4y = -1 + 4y + 1 + -4y

Reorder the terms:
1 + x2 + -4y = -1 + 1 + 4y + -4y

Combine like terms: -1 + 1 = 0
1 + x2 + -4y = 0 + 4y + -4y
1 + x2 + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
1 + x2 + -4y = 0

The solution to this equation could not be determined.

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